document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=604688>Question 604688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rewrite the quadratic equation in standard form by completing the square.<BR>\n" );
document.write( "f(x)=x^2+8x+14<BR>\n" );
document.write( "Answer (f(x)= (x, plus or minus ___)^2 plus or minus ____\r<BR>\n" );
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document.write( "I have worked this to x, 4 as well as x, -4. I have also come up with x, +8.\r<BR>\n" );
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document.write( "Also for the second answer I have some up with +14 or sqrt 2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381347 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + 8x + 16 is (x + 4)^2\r<BR>\n" );
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document.write( "when you add 2 to complete the square, you must also subtract 2 so the value of the expression stays constant\r<BR>\n" );
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document.write( "f(x) = x^2 + 8x + 14 + 2 - 2\r<BR>\n" );
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document.write( "f(x) = x^2 + 8x + 16 - 2\r<BR>\n" );
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document.write( "f(x) = (x + 4)^2 - 2  ___  this is called the vertex form of the equation, the vertex of the parabola is (-4,-2) </SPAN>\n" );
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