document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=604691>Question 604691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the logarithm equation log[4](x)+ log[4](6x-7)=log[4]5.<BR>\n" );
document.write( "Give the exact answer in the form of a fraction.<BR>\n" );
document.write( "x=____\r<BR>\n" );
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document.write( "I worked the problem and came up with two different fractions; I have x= 1/2 or x=5/3.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381343 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log[4](x)+ log[4](6x-7)=log[4]5<BR>\n" );
document.write( "log[4](x)(6x-7)=log[4]5<BR>\n" );
document.write( "(x)(6x-7)=5<BR>\n" );
document.write( "6x^2 - 7x = 5<BR>\n" );
document.write( "6x^2 - 7x - 5 = 0<BR>\n" );
document.write( "6x^2 - 10x + 3x - 5 = 0<BR>\n" );
document.write( "(6x^2 - 10x) + (3x - 5) = 0<BR>\n" );
document.write( "2x(3x - 5) + (3x - 5) = 0<BR>\n" );
document.write( "(3x - 5)(2x+1) = 0<BR>\n" );
document.write( "x = {5/3, -1/2}<BR>\n" );
document.write( "Since you can't take the log of a negative number, you can throw out -1/2 (extraneous) leaving:<BR>\n" );
document.write( "x = 5/3 </SPAN>\n" );
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