document.write( "Question 604629: Solve the equation: 4x^3+3x^2=64x+48
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Algebra.Com's Answer #381308 by lwsshak3(11628)\"\" \"About 
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Solve the equation:
\n" ); document.write( "4x^3+3x^2=64x+48
\n" ); document.write( "Try grouping
\n" ); document.write( "x^2(4x+3)=16(4x+3)
\n" ); document.write( "set to zero
\n" ); document.write( "x^2(4x+3)-16(4x+3)=0
\n" ); document.write( "factor out (4x+3)
\n" ); document.write( "(4x+3)(x^2-16)=0
\n" ); document.write( "solve for x
\n" ); document.write( "4x+3=0
\n" ); document.write( "4x=-3
\n" ); document.write( "x=-3/4
\n" ); document.write( "or
\n" ); document.write( "x^2-16=0
\n" ); document.write( "(x+4)(x-4)=0 (difference of squares)
\n" ); document.write( "x=-4
\n" ); document.write( "and
\n" ); document.write( "x=4
\n" ); document.write( "roots or zeros are: -3/4, -4 and 4
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