document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=604552>Question 604552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve below equation to get value of p , q and r   using substitution methods\r<BR>\n" );
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document.write( "p-2q + 3r= 7<BR>\n" );
document.write( "2p +3q- 2r = 32<BR>\n" );
document.write( "2p+3q -4r= 23<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381288 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve below equation to get value of p , q and r   using substitution methods\r<BR>\n" );
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document.write( "p-2q + 3r= 7<BR>\n" );
document.write( "2p +3q- 2r = 32<BR>\n" );
document.write( "2p+3q -4r= 23<BR>\n" );
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document.write( "p-2q + 3r= 7 --> p = 2q - 3r + 7<BR>\n" );
document.write( "Sub for p in the 2nd & 3rd eqns.<BR>\n" );
document.write( "That'll give 2 eqns in q & r<BR>\n" );
document.write( "solve 1 eqn for either, sub into the other eqn.<BR>\n" );
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