document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=604104>Question 604104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was given the equation: x^2+4x-6y=-10<BR>\n" );
document.write( "it says write the standard equation for the parabola. state the vertex, focus, and directrix.\r<BR>\n" );
document.write( "\n" );
document.write( "i started off with adding 6y to both sides. then i added 4 to both sides. <BR>\n" );
document.write( "now i have<BR>\n" );
document.write( "(x+2)^2=6y-6<BR>\n" );
document.write( "i am stuck. please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381278 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381278\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6y = (x + 2)^2 + 6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y = (1/6)(x + 2)^2 + 1 ___ this is the vertex form, with vertex at (-2,1)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the vertex is midway between the focus and the directrix; with the vertex and focus located on the axis of symmetry,<BR>\n" );
document.write( "and the directrix perpendicular to it\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the distance (p) from the the vertex to the focus (or the directrix) is &#9474;1 / 4a&#9474;<BR>\n" );
document.write( "___ in this case, 6/4 or 3/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "you can think of the focus as being \"inside\" the curvature of the parabola, while the directrix is \"outside\"\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "with this upward opening parabola (a is positive), the focus is above the vertex and the directrix is below it\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so the focus is (-2,5/2); and the directrix is y = -1/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );