document.write( "Question 604512: in 15 years dorothy will be 3 times as old as stan. 5 years ago the difference in their ages was 50 how old are dorothy and stan? \n" ); document.write( "
Algebra.Com's Answer #381248 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
in 15 years dorothy will be 3 times as old as stan. 5 years ago the difference in their ages was 50 how old are dorothy and stan?
\n" ); document.write( "**
\n" ); document.write( "let x=dorothy's present age
\n" ); document.write( "let y=stan's present age
\n" ); document.write( "..
\n" ); document.write( "15 years hence:
\n" ); document.write( "(x+15)=3(y+15)
\n" ); document.write( "x+15=3y+45
\n" ); document.write( "..
\n" ); document.write( "5 years ago:
\n" ); document.write( "(x-5)-(y-5)=50
\n" ); document.write( "x-5-y+5=50
\n" ); document.write( "x-y=50
\n" ); document.write( "x=50+y
\n" ); document.write( "..
\n" ); document.write( "x+15=3y+45
\n" ); document.write( "sub (50+y) for x
\n" ); document.write( "50+y+15=3y+45
\n" ); document.write( "2y=20
\n" ); document.write( "y=10
\n" ); document.write( "x=50+y=60
\n" ); document.write( "ans:
\n" ); document.write( "dorothy's present age=60
\n" ); document.write( "let y=stan's present age=10\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );