document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=604413>Question 604413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many kilograms of water must be added to 12kg of a 30% salt solution to produce a 20% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381214 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> water means 0% salt solution<BR>\n" );
document.write( "let water = x kilograms\r<BR>\n" );
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document.write( "0%*x + 30%*12 = 20%*(x + 12)<BR>\n" );
document.write( "(omit all the % sign)<BR>\n" );
document.write( "0*x + 30*12 = 20*(x + 12)<BR>\n" );
document.write( "0 + 360 = 20x + 240<BR>\n" );
document.write( "360 - 240 = 20x<BR>\n" );
document.write( "120 = 20x<BR>\n" );
document.write( "x = 120/20 = 6\r<BR>\n" );
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document.write( "so we must add 6 kilograms of water<BR>\n" );
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