document.write( "Question 56124: What is 4+ the square root of 2x-5=x \n" ); document.write( "
Algebra.Com's Answer #38116 by ankor@dixie-net.com(22740)\"\" \"About 
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What is 4+ the square root of 2x-5=x
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\n" ); document.write( "4 + SqRt(2x-5) = x
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\n" ); document.write( "SqRt(2x-5) = x - 4; subtracted 4 from both sides
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\n" ); document.write( "2x - 5 = x^2 - 8x + 16; squared both sides, FOILed (x-4)^2
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\n" ); document.write( "0 = x^2 - 8x - 2x + 16 + 5, arrange on the right,
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\n" ); document.write( "x^2 - 10x + 21 = 0; our old friend, the quadratic equation
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\n" ); document.write( "Easily factored:
\n" ); document.write( "(x-3)(x-7) = 0
\n" ); document.write( "x = +3
\n" ); document.write( "x = +7
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\n" ); document.write( "Check both solutions, especially when dealing with square roots.
\n" ); document.write( "4 + SqRt(2(3) - 5) = 3
\n" ); document.write( "4 + SqRt(1) = 5 not 3 as required, x=3 is not a solution
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\n" ); document.write( "Try x = 7
\n" ); document.write( "4 + SqRt(2(7) - 5) = 7
\n" ); document.write( "4 + SqRt(9) = 7; x = 7 is a good solution
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