document.write( "Question 604292: A picture that measures 7 inches by 7 inches is being framed. The area of the frame is 32 square inches. What is the widt of the frame? \n" ); document.write( "

Algebra.Com's Answer #381081 by alicealc(293) $\"\"$ $\"About$

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Let frame width and length = 7 + 2x (plus x on both sides, so it makes 2x)\r
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\n" ); document.write( "\n" ); document.write( "(7 + 2x)*(7 + 2x) - 7*7 = 32
\n" ); document.write( "49 + 14x + 14x + 4x^2 - 49 = 32
\n" ); document.write( " $\"4x%5E2+%2B+28x+=+32\"$
\n" ); document.write( " $\"4x%5E2+%2B+28x+-+32+=+0\"$
\n" ); document.write( "(divide all by 4)
\n" ); document.write( " $\"x%5E2+%2B+7x+-+8+=+0\"$
\n" ); document.write( "(x + 8)(x - 1) = 0
\n" ); document.write( "x + 8 = 0 or x - 1 = 0
\n" ); document.write( "x = -8 or x = 1
\n" ); document.write( "because the size can't be a negative number, so we take x = 1\r
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\n" ); document.write( "\n" ); document.write( "so the frame width and length are the same, that is 7 + 2*1 = 7 + 2 = 9 inches
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