document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56173>Question 56173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x^2 + x - 2 = 0\r<BR>\n" );
document.write( "\n" );
document.write( "I am just learning this...Help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38106 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6X^2+X-2=0 YOU NEED TO FIND TWO FACTORS OF 6 (1,6 OR 2.3) THAT WHEN MULTIPLIED BY THE FACTORS OF -2 (1,-2 OR -1,2) EQUALS 1.<BR>\n" );
document.write( "THUS <BR>\n" );
document.write( "(3X+2)(2X-1)=0<BR>\n" );
document.write( "NOW SOLVE BOTH OF THESE FACTORS BY SETTING EACH EQUAL T0 0<BR>\n" );
document.write( "3X+2=0<BR>\n" );
document.write( "3X=-2<BR>\n" );
document.write( "X=-2/3<BR>\n" );
document.write( "AND<BR>\n" );
document.write( "2X-1=0<BR>\n" );
document.write( "2X=1<BR>\n" );
document.write( "X=1/2<BR>\n" );
document.write( "PROOF IS REPLACING X BY -2/3 & THEN BY 1/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );