document.write( "Question 56173: 6x^2 + x - 2 = 0\r
\n" ); document.write( "\n" ); document.write( "I am just learning this...Help!
\n" ); document.write( "

Algebra.Com's Answer #38105 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
6x^2 + x - 2 = 0
\n" ); document.write( "
\n" ); document.write( "Factoras follows:
\n" ); document.write( "(3x+2)(2x-1)=0
\n" ); document.write( "Since the product is zerot one
\n" ); document.write( "of these factors must be zero.
\n" ); document.write( "3x+2 =0 or 2x-1=0
\n" ); document.write( "If 3x+2=0
\n" ); document.write( "Then 3x=-2
\n" ); document.write( "x=-2/3
\n" ); document.write( "--------
\n" ); document.write( "If 2x-1=0
\n" ); document.write( "Then 2x=1
\n" ); document.write( "x=1/2
\n" ); document.write( "So, x=-2/3 or x=1/2
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );