document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=604245>Question 604245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> explain the squareroot of 180 minus the squareroot of 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381036 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem you are given is to simplify:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28180%29+-+sqrt%285%29 ALIGN=MIDDLE  ALT=\"sqrt%28180%29+-+sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Begin by factoring the 180. Since this problem has the goal of teaching you something about simplifying radicals, you can assume the likelihood that 5 is a good factor to try and that somehow the square root of 5 will be involved in both terms of the expression you are given. So factoring 5 from 180 results in the two term expression becoming:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2836%2A5%29+-+sqrt%285%29 ALIGN=MIDDLE  ALT=\"sqrt%2836%2A5%29+-+sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "But, by the rules of radicals, the first term can now become the product of the radicals of the two factors and the expression is then:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2836%29%2Asqrt%285%29+-+sqrt%285%29 ALIGN=MIDDLE  ALT=\"sqrt%2836%29%2Asqrt%285%29+-+sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Next, note that the square root of 36 is 6. Substituting 6 for the square root of 36 results in:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6%2Asqrt%285%29+-+sqrt%285%29 ALIGN=MIDDLE  ALT=\"6%2Asqrt%285%29+-+sqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Then note that the square root of 5 is a common factor of both terms. If you factor it from both of the terms you get the distributed multiplication:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%286+-+1%29%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"%286+-+1%29%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "and in the parentheses you can subtract 1 from 6 to get 5. Substituting this 5 for (6 - 1) gives the answer:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"5%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "And this is a step-by-step method of solving the given problem.<BR>\n" );
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document.write( "I hope this helps you to understand some procedures you can use when working with radicals to simplify algebraic expressions.<BR>\n" );
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