document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=604244>Question 604244</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a polynomial of lowest degree that has real coefficients, a leading coefficient of 1, and with 3 and 2+i as two of its zeros.\r<BR>\n" );
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document.write( "I got as far as:<BR>\n" );
document.write( "f(x)= (x-3)(x-(2+i))(x-(2-i)), but then I am completely stuck.\r<BR>\n" );
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document.write( "I appreciate the help, thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381022 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-3)(x-(2+i))(x-(2-i))= (x-3) ( (x-2)^2+1))= (x-3) ( x^2-4x+5)<BR>\n" );
document.write( "= x^3 -7x^2+7x-15 </SPAN>\n" );
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