document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1296>Question 1296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by using subsitution<BR>\n" );
document.write( "y=x<BR>\n" );
document.write( "y=-x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #381 by </B><A HREF=/tutors/aboutme.mpl?userid=iamlegallyblond7><B>iamlegallyblond7(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=iamlegallyblond7><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if y=x, then in the equation, wherever there is a y, enter an x<BR>\n" );
document.write( "so if the equation is y=-x+2, there is one y<BR>\n" );
document.write( "so if i substitute in x, it will be:<BR>\n" );
document.write( "x=-x+2<BR>\n" );
document.write( "then you solve the problem </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );