document.write( "Question 56143: the lenghs of a rectangleis twice the the width. the perimeter is 84 cm more than the width. make a digram and find the rectangle's dimensions. \n" ); document.write( "
Algebra.Com's Answer #38099 by ankor@dixie-net.com(22740)\"\" \"About 
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:
\n" ); document.write( "the lengths of a rectangle is twice the the width.
\n" ); document.write( "L = 2W\r
\n" ); document.write( "\n" ); document.write( "the perimeter is 84 cm more than the width.
\n" ); document.write( "2L + 2W = W + 84
\n" ); document.write( ":
\n" ); document.write( "Substitute 2W for L (from the 1st equation)
\n" ); document.write( "2(2W) + 2W = W + 84
\n" ); document.write( "4W + 2W - W = 84
\n" ); document.write( " 5W = 84
\n" ); document.write( " W = 84/5
\n" ); document.write( " W = 16.8 cm
\n" ); document.write( ":
\n" ); document.write( "L = 2 * 16.8 = 33.6 cm
\n" ); document.write( ":
\n" ); document.write( "A rectangle 33.6 by 16.8
\n" ); document.write( ":
\n" ); document.write( "Check it using the perimeter:
\n" ); document.write( "2(33.6) + 2(16.8) = 100.8 which is 84 cm more than (16.8). the width
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "I'll let you make a digram. \n" ); document.write( "
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