document.write( "Question 603932: Tom and Carl start 200 miles apart, running towards each other. Tom runs 5 miles per hour faster than Carl. If they meet after 10 hours, how fast are they running?\r
\n" ); document.write( "\n" ); document.write( "A. 10 mph and 15 mph
\n" ); document.write( "B. 15 mph and 20 mph
\n" ); document.write( "C. 2.5 mph and 7.5 mph
\n" ); document.write( "D. 7.5 mph and 12.5 mph
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Algebra.Com's Answer #380885 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Tom runs 5 miles per hour faster than Carl
\n" ); document.write( "Let r AND (r+5) represent Carl's and Toms's speeds respectively
\n" ); document.write( "Question states***
\n" ); document.write( "Tom and Carl start 200 miles apart, running towards each other.
\n" ); document.write( "they meet after 10 hours
\n" ); document.write( "Note: d = rt
\n" ); document.write( " rt + (r+5)t = 200
\n" ); document.write( " t[r +(r+5)] = 200
\n" ); document.write( " t = 200/(2r+5) = 10hrs
\n" ); document.write( "Solving for r
\n" ); document.write( "10(2r+5) = 200
\n" ); document.write( " 2r + 5 = 20
\n" ); document.write( " 2r = 15
\n" ); document.write( " r = 7.5, carls speed, tom's speed is 12.5
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 7.5·10 + 12.5·10 = 75 + 125 = 200mi \n" ); document.write( "
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