document.write( "Question 603886: Can you help me solve the equations ax + by = m and cx + dy = n. somehow the answer is supposed to be those two equations combined into one. \r
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document.write( "I need an answer asap\r
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document.write( "everything I have done is wrong and I need to know how to figure them out.
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Algebra.Com's Answer #380866 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Can you help me solve the equations ax + by = m and cx + dy = n. \n" ); document.write( "----------- \n" ); document.write( "Use determinants\r \n" ); document.write( "\n" ); document.write( "|a b -m| \n" ); document.write( "|c d -n| \n" ); document.write( "--------- \n" ); document.write( "Det = ab - cd \n" ); document.write( "--- \n" ); document.write( "x*Det = b*-n - d*-m = dm - bn \n" ); document.write( "-y*Det = a*-n - c*-m = cm - an \n" ); document.write( "-------- \n" ); document.write( "x = (dm - bn)/(ab - cd) \n" ); document.write( "y = (an - cm)/(ab - cd) \n" ); document.write( "=========================== \n" ); document.write( "Without determinants: \n" ); document.write( "ax + by = m Eqn 1 \n" ); document.write( "cx + dy = n Eqn 2 \n" ); document.write( "------ \n" ); document.write( "acx + bcy = cm Eqn 1 times c \n" ); document.write( "acx + ady = an Eqn 2 times a \n" ); document.write( "------------------------ Subtract \n" ); document.write( "y*(bc-ad) = cm - an \n" ); document.write( "y = (an - cm)/(ad - bc) (I flipped both NUM and DEN) \n" ); document.write( "========================\r \n" ); document.write( "\n" ); document.write( "ax + by = m Eqn 1 \n" ); document.write( "cx + dy = n Eqn 2 \n" ); document.write( "------ \n" ); document.write( "adx + bdy = dm Eqn 1 times d \n" ); document.write( "bcx + bdy = bn Eqn 2 times b \n" ); document.write( "------------------------ Subtract \n" ); document.write( "x*(ad - bc) = dm - bn \n" ); document.write( "x = (dm - bn)/(ad - bc)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |