document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=603784>Question 603784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sonny is twice as old as david. Four years ago, he was four times as old as david. When will the sum of their ages be 66? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380835 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In 24 years the sum of both the ages = 66\r<BR>\n" );
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document.write( "You can check step by step solution from the below link<BR>\n" );
document.write( "http://www.algebraden.com/solved-problems/find-years/32.htm\r<BR>\n" );
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document.write( "Hope this will help you. </SPAN>\n" );
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