document.write( "Question 603785: Find the dimensions of a photo that has an area of 48 sq. in and a perimeter of 28 in. \n" ); document.write( "
Algebra.Com's Answer #380829 by mananth(16949)\"\" \"About 
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let length = x in
\n" ); document.write( "width = y in
\n" ); document.write( "Perimeter
\n" ); document.write( "2(x+y) = 28
\n" ); document.write( "x+y = 14\r
\n" ); document.write( "\n" ); document.write( "Area
\n" ); document.write( "xy = 48
\n" ); document.write( "x= 48/y\r
\n" ); document.write( "\n" ); document.write( "substitute x \r
\n" ); document.write( "\n" ); document.write( "x+y =14
\n" ); document.write( "48/y + y = 14\r
\n" ); document.write( "\n" ); document.write( "multiply equation by y\r
\n" ); document.write( "\n" ); document.write( "48+y^2=14y\r
\n" ); document.write( "\n" ); document.write( "y^2-14y+48=0\r
\n" ); document.write( "\n" ); document.write( "y^2-8y-6y+48=0
\n" ); document.write( "y(y-8)-6(y-8)=0
\n" ); document.write( "(y-8)(y-6)=0\r
\n" ); document.write( "\n" ); document.write( "y = 6 OR 8\r
\n" ); document.write( "\n" ); document.write( "the dimensions are 8 in by 6 in
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