document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=603613>Question 603613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for log(3x-1) + log2= log4 + log(x+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380799 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for <BR>\n" );
document.write( "log(3x-1) + log2= log4 + log(x+2)<BR>\n" );
document.write( "log(3x-1) + log2- log4 - log(x+2)=0<BR>\n" );
document.write( "log(3x-1) + log2- [log4 + log(x+2)]=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log[(3x-1)*2/4*(x+2)]=0<BR>\n" );
document.write( "convert to exponential form: base(10) raised to log of number(0)=number[(3x-1)*2/4*(x+2)]<BR>\n" );
document.write( "10^0=[(3x-1)*2/4*(x+2)]=1<BR>\n" );
document.write( "2(3x-1)=4(x+2)<BR>\n" );
document.write( "6x-2=4x+8<BR>\n" );
document.write( "2x=10<BR>\n" );
document.write( "x=5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );