document.write( "Question 603675: A motorist travels for 3okm at xkm/h and for 9okm at ykm/h and takes place 2.5hours for the journey. if the speed are interchanging, the journey take 2whole number 1/6 find x and y \n" ); document.write( "
Algebra.Com's Answer #380786 by mananth(16949) You can put this solution on YOUR website! Distance = speed * time\r \n" ); document.write( "\n" ); document.write( "Time = distance/speed\r \n" ); document.write( "\n" ); document.write( "t=d/r \n" ); document.write( "First condition\r \n" ); document.write( "\n" ); document.write( "Time Part I + time part II = 2.5 hour\r \n" ); document.write( "\n" ); document.write( "30/x+90/y = 2.5\r \n" ); document.write( "\n" ); document.write( "Let 1/x=a & 1/y = b\r \n" ); document.write( "\n" ); document.write( "30a+90b=5/2.......................(1)\r \n" ); document.write( "\n" ); document.write( "Second condition\r \n" ); document.write( "\n" ); document.write( "90/x+30/y = 2 1/6 = 13/6\r \n" ); document.write( "\n" ); document.write( "90a+30b= 13/6......................(2)\r \n" ); document.write( "\n" ); document.write( "add (1) & (2) \n" ); document.write( "120a+120b=5/2+13/6 \n" ); document.write( "120a+120b=14/3 \n" ); document.write( "divide by 120 \n" ); document.write( "a+b= 14/360.............(3)\r \n" ); document.write( "\n" ); document.write( "(1)-(2)\r \n" ); document.write( "\n" ); document.write( "-60a+60b=1/3 \n" ); document.write( "divide by -60 \n" ); document.write( "a-b=-1/180...................(4)\r \n" ); document.write( "\n" ); document.write( "(3)+(4) \n" ); document.write( "2a= 14/360-1/180\r \n" ); document.write( "\n" ); document.write( "a=7/360 -1/360 \n" ); document.write( "a= 6/360 \n" ); document.write( "a=1/60 \n" ); document.write( "1/x= 1/60 \n" ); document.write( "x= 60 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a+b = 14/360 \n" ); document.write( "b= 14/360 -1/60 \n" ); document.write( "b=8/360 \n" ); document.write( "b=1/y = 8/360 \n" ); document.write( "y= 360/8 \n" ); document.write( "y=45\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |