document.write( "Question 603675: A motorist travels for 3okm at xkm/h and for 9okm at ykm/h and takes place 2.5hours for the journey. if the speed are interchanging, the journey take 2whole number 1/6 find x and y \n" ); document.write( "
Algebra.Com's Answer #380786 by mananth(16949)\"\" \"About 
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Distance = speed * time\r
\n" ); document.write( "\n" ); document.write( "Time = distance/speed\r
\n" ); document.write( "\n" ); document.write( "t=d/r
\n" ); document.write( "First condition\r
\n" ); document.write( "\n" ); document.write( "Time Part I + time part II = 2.5 hour\r
\n" ); document.write( "\n" ); document.write( "30/x+90/y = 2.5\r
\n" ); document.write( "\n" ); document.write( "Let 1/x=a & 1/y = b\r
\n" ); document.write( "\n" ); document.write( "30a+90b=5/2.......................(1)\r
\n" ); document.write( "\n" ); document.write( "Second condition\r
\n" ); document.write( "\n" ); document.write( "90/x+30/y = 2 1/6 = 13/6\r
\n" ); document.write( "\n" ); document.write( "90a+30b= 13/6......................(2)\r
\n" ); document.write( "\n" ); document.write( "add (1) & (2)
\n" ); document.write( "120a+120b=5/2+13/6
\n" ); document.write( "120a+120b=14/3
\n" ); document.write( "divide by 120
\n" ); document.write( "a+b= 14/360.............(3)\r
\n" ); document.write( "\n" ); document.write( "(1)-(2)\r
\n" ); document.write( "\n" ); document.write( "-60a+60b=1/3
\n" ); document.write( "divide by -60
\n" ); document.write( "a-b=-1/180...................(4)\r
\n" ); document.write( "\n" ); document.write( "(3)+(4)
\n" ); document.write( "2a= 14/360-1/180\r
\n" ); document.write( "\n" ); document.write( "a=7/360 -1/360
\n" ); document.write( "a= 6/360
\n" ); document.write( "a=1/60
\n" ); document.write( "1/x= 1/60
\n" ); document.write( "x= 60 \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a+b = 14/360
\n" ); document.write( "b= 14/360 -1/60
\n" ); document.write( "b=8/360
\n" ); document.write( "b=1/y = 8/360
\n" ); document.write( "y= 360/8
\n" ); document.write( "y=45\r
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