document.write( "Question 603582: Alice is as old as Betty and Christine together. Last year, Betty was twice as old a Christine. Two years hence, Alice will be twice as old as Christine. What are the ages of the three girls? \n" ); document.write( "
Algebra.Com's Answer #380753 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Alice is as old as Betty and Christine together. Last year, Betty was twice as old a Christine. \n" ); document.write( " Two years hence, Alice will be twice as old as Christine. \n" ); document.write( " What are the ages of the three girls? \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "\"Alice is as old as Betty and Christine together. \n" ); document.write( "a = b + c \n" ); document.write( ": \n" ); document.write( "\"Last year, Betty was twice as old a Christine.\" \n" ); document.write( "b - 1 = 2(c-1) \n" ); document.write( "b - 1 = 2c - 2 \n" ); document.write( "b = 2c - 2 + 1 \n" ); document.write( "b = 2c - 1 \n" ); document.write( ": \n" ); document.write( "\"Two years hence, Alice will be twice as old as Christine.\" \n" ); document.write( "a + 2 = 2(c+2) \n" ); document.write( "a + 2 = 2c + 4 \n" ); document.write( "a = 2c + 4 - 2 \n" ); document.write( "a = 2c + 2 \n" ); document.write( ": \n" ); document.write( "the 1st equation \n" ); document.write( "a = b + c \n" ); document.write( "replace a with (2c+2). replace b with (2c-1) \n" ); document.write( "2c + 2 = 2c - 1 + c \n" ); document.write( "2 + 1 = c \n" ); document.write( "c = 3 yrs old \n" ); document.write( "then \n" ); document.write( "a = 2(3) + 2 \n" ); document.write( "a = 8 yrs old \n" ); document.write( "and \n" ); document.write( "b = 2(3) - 1 \n" ); document.write( "b = 5 yrs old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " What are the ages of the three girls? 8, 5, 3 \n" ); document.write( " |