document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=603473>Question 603473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A canoe covers a distance of 40 miles downstream in 6 hours. Returning upstream, it takes the canoe three times as long to cover 3/5 the distance. Find the rate of the current and the rate of the canoe in still water.\r<BR>\n" );
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document.write( "Note: The answer alone is insufficient. You must not only show your work (define your variables and write two equations, solving the system) but also explain your process in order to receive full credit for you answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380725 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380725\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let s=rate of stream (current) and c=rate of canoe\r<BR>\n" );
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document.write( "going downstream, the rates add ___ going upstream, the current is subtracted from the canoe<BR>\n" );
document.write( "___ the calculations are in miles and hours\r<BR>\n" );
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document.write( "r = d / t\r<BR>\n" );
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document.write( "down ___ c + s = 40 / 6 = 20/3\r<BR>\n" );
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document.write( "up ___ c - s = [(3/5) * 40] / (3 * 6) = 4/3\r<BR>\n" );
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document.write( "adding the equations (eliminating s) ___ 2c = 24/3 ___ c = 4 mph\r<BR>\n" );
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document.write( "substituting (to find s) ___ (4) + s = 20/3 ___ s = 20/3 - 12/3 = 8/3 mph </SPAN>\n" );
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