document.write( "Question 603206: I don't know how to solve for the area of a triangle with a height of 5xsqrt and a base of 10x to the sixth power. \n" ); document.write( "
Algebra.Com's Answer #380631 by KMST(5347)\"\" \"About 
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NOTE:
\n" ); document.write( "I may be misinterpreting \"5xsqrt\" and or \"10x to the sixth power\"
\n" ); document.write( "The conventional way to type square roots and powers is like this:
\n" ); document.write( "\"sqrt%28x%29\"=sqrt(x) , \"10x%5E6=10%2Ax%5E6\"=10x^6=10*x^6 , and \"%2810x%29%5E6\"=(10x)^6
\n" ); document.write( "We use ^ to indicate that the exponent is written higher than the rest; we use * to indicate multiplication, and we use sqrt( ) when we mean square root, with whatever is under the radical sign in the brackets.
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\n" ); document.write( "IF THE PROBLEM WAS \"base=10x%5E6\" and \"height=5sqrt%28x%29\"
\n" ); document.write( "You must know that the area of a triangle can be calculated as 1/2 times base, times height.
\n" ); document.write( "\"area=%281%2F2%29%2810x%5E6%29%285sqrt%28x%29%29\"
\n" ); document.write( "That can be simplified somewhat.
\n" ); document.write( "Because of the associative and commutative properties, numbers and expressions that are multiplied together can be multiplied in any order, grouping them in any way, with the same result.
\n" ); document.write( "You have \"1%2F2\" \"10\" \"x%5E6\" \"5\" and \"sqrt%28x%29\" multiplied together, grouped by brackets in a certain way. The resulting product is the same if the grouping and order is changed to a more convenient way:
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\n" ); document.write( "So \"area=%28%281%2F2%29%2A10%2A5%29%28x%5E6%2Asqrt%28x%29%29\"
\n" ); document.write( "We can do the indicated multiplication, and there are different ways to express it, but I like
\n" ); document.write( "\"area=25x%5E6%2Asqrt%28x%29\" or the same thing without the dot between \"x%5E6\" and \"sqrt%28x%29\".
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\n" ); document.write( "IF THE PROBLEM WAS \"base=%2810x%29%5E6\" and \"height=5sqrt%28x%29\"
\n" ); document.write( "you must know that \"%2810x%29%5E6=10%5E6%2Ax%5E6=1000000x%5E6\"
\n" ); document.write( "but the rest of the calculation is done in a similar way.
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