document.write( "Question 603183: how much pure acid must be mixed into 100ml of 20% acid to create a solution of 60% acid? \n" ); document.write( "
Algebra.Com's Answer #380618 by mananth(16946)\"\" \"About 
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-------------- percent ---------------- Amount
\n" ); document.write( "Acid solution 20 ---------------- 100 ml
\n" ); document.write( "Pure acid 100 ---------------- x ml
\n" ); document.write( "Mixture 60 ---------------- 100 + x ml
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\n" ); document.write( "20*100 +100x =60(100 +x)
\n" ); document.write( "2000+ 100x=6000+60x
\n" ); document.write( "100x-60x=-2000+ 6000
\n" ); document.write( "40 x = 4000
\n" ); document.write( "/ 40
\n" ); document.write( "x = 100 ml Pure acid
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\n" ); document.write( "m.ananth@hotmail.ca
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