document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=603102>Question 603102</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object is moving at a speed of (3+2^(1/2)) ft/s.  How long will it take the object to travel 20 ft? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380571 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An object is moving at a speed of (3+2^(1/2)) ft/s. How long will it take the object to travel 20 ft?<BR>\n" );
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document.write( "time = distance/rate<BR>\n" );
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document.write( "time = 20 ft/(3+sqrt(3))(ft/sec)<BR>\n" );
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document.write( "= [20(3-sqrt(3))]/[(3+sqrt(3))(3-sqrt(3)]<BR>\n" );
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document.write( "= [20(3-sqrt(3)]/[9-3]<BR>\n" );
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document.write( "= (10/3)(3-sqrt(3))<BR>\n" );
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document.write( "= 10 - (10/3)sqrt(3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "======================== </SPAN>\n" );
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