document.write( "Question 603010: Determine the smaller angle between the hands of a clock at 12:20. Show or explain how you got your answer. \n" ); document.write( "

Algebra.Com's Answer #380525 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "The angular difference between the 12 where the minute hand was at exactly 12 and the 4 which is where the minute hand is at exactly 12:20 is exactly one-third of a circle. But while the minute hand was moving through this one-third of the whole circle, the hour hand was moving one-third of the way from the 12 (where it was at 12 o'clock exactly) to the 1 (where it will be when the minute hand gets all the way back around to the 12). The angular difference between the 12 and the 1 is one-twelfth of a circle. So the minute hand has moved a full one-third of the circle but the hour hand has moved one-third of one-twelfth of the circle. Then recall that there are 360 degrees in a circle.\r
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\n" ); document.write( "\n" ); document.write( "You Win! You get to do your own arithmetic.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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