document.write( "Question 56088: An investor puts $3000 in 2 CDs, one of which earns 5% annually and the other earns 4% annually. After 2 years he has earned $260. How much has he invested in each CD?\r
\n" ); document.write( "\n" ); document.write( "Can anyone solve this for me? I am a total math loser!!\r
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Algebra.Com's Answer #38052 by tutorcecilia(2152)\"\" \"About 
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After 2 years he has earned $260.
\n" ); document.write( "Since the amount earned is $260 for two years, divide by 2 to get the amount earned in one year:
\n" ); document.write( "260/2=$130 interest earned in one year
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\n" ); document.write( "So,
\n" ); document.write( "x invested at 4% plus($3000-x)invested at 5%=$130 interest earned in one year.
\n" ); document.write( ".04x+.05(3000-x)=130
\n" ); document.write( ".04x+150-.05=130
\n" ); document.write( ".04x-.05x=130-150
\n" ); document.write( "-.01x=-20
\n" ); document.write( "x=$2000
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\n" ); document.write( "The CD at 4% earned = (.04)(2000)=$80 per year or $160 per two years
\n" ); document.write( "The CD at 5% earned=(.05)($3000-$2000)=$50 per year or 100 per two years.
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