document.write( "Question 602872: Assume that abcd is a rhombus. Prove that ac is prependicular to bd (let e be the point of intersection$ \n" ); document.write( "
Algebra.Com's Answer #380488 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Draw the diagonals forming 4 triangles. Since it is a rhombus, it is also a parallelogram. The diagonals of a parallelogram bisect each other.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AB congruent AD, defn of rhombus\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AE congruent AE, reflexive equality\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "BE congruent DE, diagonals of parallelogram bisect each other\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Triangle ABE congruent triangle ADE by SSS\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle BED is a straight angle, hence measures 180 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle AEB congruent Angle AED by CPCT\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "measure of BED equals measure AEB + measure AED\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "measure of BED equals 2 times measure AEB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "measure AEB is 90\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "QED.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |