document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602880>Question 602880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Soren had a 36 mile head start.  If Eric caught him in 3 hrs, how fast was Eric traveling if his speed was 2x Sorens?\r<BR>\n" );
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document.write( "I know D=RT.  I assume they both went the same distance because Eric caught up.  I made the equation 2 different ways.  The first one was like this:\r<BR>\n" );
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document.write( "RT=RT<BR>\n" );
document.write( "(Sorens RT)=(Erics RT)  I came up with 1/2, and I know this is not right.  \r<BR>\n" );
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document.write( "I then tried (Sorens RT)=(Erics RT)+36, and I get a -12.  I am not sure what I am doing wrong.  Can you please help me?  \r<BR>\n" );
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document.write( "Thanks,<BR>\n" );
document.write( "Sheila </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380474 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Soren had a 36 mile head start\" ___ so they were not traveling the same distance\r<BR>\n" );
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document.write( "E * 3 = [(E/2) * 3] + 36\r<BR>\n" );
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document.write( "multiplying by 2 (to clear fraction) ___ 6E = 3E + 72 </SPAN>\n" );
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