document.write( "Question 602880: Soren had a 36 mile head start. If Eric caught him in 3 hrs, how fast was Eric traveling if his speed was 2x Sorens?\r
\n" ); document.write( "\n" ); document.write( "I know D=RT. I assume they both went the same distance because Eric caught up. I made the equation 2 different ways. The first one was like this:\r
\n" ); document.write( "\n" ); document.write( "RT=RT
\n" ); document.write( "(Sorens RT)=(Erics RT) I came up with 1/2, and I know this is not right. \r
\n" ); document.write( "\n" ); document.write( "I then tried (Sorens RT)=(Erics RT)+36, and I get a -12. I am not sure what I am doing wrong. Can you please help me? \r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( "Sheila
\n" ); document.write( "

Algebra.Com's Answer #380472 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Soren's head start was \"+36+\" mi
\n" ); document.write( "Start a stop watch when Eric leaves.
\n" ); document.write( "Let \"+d+\" = distance that Eric travels
\n" ); document.write( "Let \"+s+\" = Soren's speed
\n" ); document.write( "They will both travel for the same amount of time, \"+3+\" hrs
\n" ); document.write( "until Soren is caught.
\n" ); document.write( "Soren's equation:
\n" ); document.write( "(1) \"+d+-+36+=+s%2A3+\"
\n" ); document.write( "Eric's equation:
\n" ); document.write( "(2) \"+d+=+2s%2A3+\"
\n" ); document.write( "---------------
\n" ); document.write( "This is 2 equations and 2 unknowns, so it's solvable
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+6s+-+36+=+3s+\"
\n" ); document.write( "(1) \"+3s+=+36+\"
\n" ); document.write( "(1) \"+s+=+12+\"
\n" ); document.write( "\"+2s+=+24+\"
\n" ); document.write( "Eric's speed is 24 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+-+36+=+s%2A3+\"
\n" ); document.write( "(1) \"+d+-+36+=+12%2A3+\"
\n" ); document.write( "(1) \"+d+=+36+%2B+36+\"
\n" ); document.write( "(1) \"+d+=+72+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+2s%2A3+\"
\n" ); document.write( "(2) \"+d+=+2%2A12%2A3+\"
\n" ); document.write( "(2) \"+d+=+72+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );