document.write( "Question 602771: The probability that Pete will catch fish on a particular day when he goes fishing is .8. Pete is going fishing 3 days next week. The probability that Pete will catch fish on two or more days is? \n" ); document.write( "
Algebra.Com's Answer #380460 by scott8148(6628) You can put this solution on YOUR website! this is a binomial problem, he either catches fish or doesn't ___ the two probabilities sum to one\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c = probability of catching = .8 ___ n = probability of not catching = .2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the binomial is raised to the 3rd power (3 days)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(c + n)^3 = c^3 + 3c^2n + 3cn^2 + n^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for 2 or more days, the first two terms (with c^3 and c^2 are added) \n" ); document.write( "___ P(≥ 2 days) = .8^3 + 3 * .8^2 * .2 = .512 + .384 \n" ); document.write( " |