document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602789>Question 602789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A racing team can paddle their canoe 11 miles downstream in the same time it takes to paddle 3 miles upstream in a 2 mile per hour current. How fast can they paddle in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380454 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the normal speed<BR>\n" );
document.write( "c is the speed of the current<BR>\n" );
document.write( "speed downstream : x+c<BR>\n" );
document.write( "speed upstream : x-c<BR>\n" );
document.write( "speed = distance/time<BR>\n" );
document.write( "c = 2 mph<BR>\n" );
document.write( "speed downstream = distance /time = x+2 = 11/t<BR>\n" );
document.write( "t= 11/(x+2)<BR>\n" );
document.write( "speed upstream = x-2 = 3/t<BR>\n" );
document.write( "t= 3/(x-2)<BR>\n" );
document.write( "t=t<BR>\n" );
document.write( "so x = 7/2 = 3.5 mph in still water\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );