document.write( "Question 602851: 3x(x-3)=2x(x+2)+6, so far I've got 3x^2-9x-2x^2-4x-6=0, then x^2-13x-6=0 but after this I'm lost? \n" ); document.write( "
Algebra.Com's Answer #380451 by flame8855(424)\"\" \"About 
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x^2-13x-6=0 a = 1 , b= -13 , c = -6
\n" ); document.write( "delta = b^2-4ac = 169+24=193
\n" ); document.write( "x1= -b+delta^2/2a = (13+193^1/2) /2
\n" ); document.write( "x2= -b-delta^2/2a = (13-193^1/2) /2
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