document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602819>Question 602819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a square is (4x^2-12x+9) sq.cm.The width of a rectangle is five cm greater than a side of the square while the length of the rectangle is twice the side of the square.What is the area, in sq.cm. of the rectangle? please show me the steps.\r<BR>\n" );
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document.write( "A.16x^2-12x-14  <BR>\n" );
document.write( "B.8x^2+10x-12 <BR>\n" );
document.write( "C.4x^2-8x-16  <BR>\n" );
document.write( "D.4x^2+2x-2  <BR>\n" );
document.write( "E.None of these </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380412 by </B><A HREF=/tutors/aboutme.mpl?userid=flame8855><B>flame8855(424)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=flame8855><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=flame8855><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x^2-12x+9 is the area of the square<BR>\n" );
document.write( "4x^2-12x+9= s^2 = (2x-3)^2<BR>\n" );
document.write( "so the side of the square is 2x-3<BR>\n" );
document.write( "the width = 2x-3+5=2x+2<BR>\n" );
document.write( "the length = 2(2x-3)=4x-6<BR>\n" );
document.write( "area= L*W= (2x+2)(4x-6)= 8x^2-12x+8x-12= 8x^2-4x-12<BR>\n" );
document.write( "so none of the above<BR>\n" );
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