document.write( "Question 602155: Delia can finish a job in 8 hours. Daisy can doit in 5 hours. if delia worked for 3 hours and then daisy was asked to help her finish it,? how long will daisy have to work with delia to finish the job? \n" ); document.write( "
Algebra.Com's Answer #380378 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Delia can finish a job in 8 hours. Daisy can doit in 5 hours.
\n" ); document.write( "if delia worked for 3 hours and then daisy was asked to help her finish it,?
\n" ); document.write( " how long will daisy have to work with delia to finish the job?
\n" ); document.write( ":
\n" ); document.write( "let t = time that Daisy worked to finish the job
\n" ); document.write( "then
\n" ); document.write( "(t+3) = total time worked by Delia
\n" ); document.write( ":
\n" ); document.write( "Let the finished job = 1
\n" ); document.write( ";
\n" ); document.write( "\"%28%28t%2B3%29%29%2F8\" + \"t%2F5\" = 1
\n" ); document.write( "Multiply by 40 to clear the denominators, results
\n" ); document.write( "5(t+3) + 8t = 40
\n" ); document.write( "5t + 15 + 8t = 40
\n" ); document.write( "13t = 40 - 15
\n" ); document.write( "13t = 25
\n" ); document.write( "t = \"25%2F13\" = 1.923 hrs which is 1 hr 55.4 minutes (worked by Daisy to finish the job)
\n" ); document.write( "
\n" );