document.write( "Question 602084: The sum of the ages of Jones' four children is 25. Maria's oldest brother is six times as old as she is. Her next-to-oldest brother is 5 years older than she is, and the youngest brother is twice Maria's age. What are the ages of the Jones' four children? \n" ); document.write( "
Algebra.Com's Answer #380375 by ankor@dixie-net.com(22740)\"\" \"About 
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The sum of the ages of Jones' four children is 25. Maria's oldest brother is six times as old as she is.
\n" ); document.write( " Her next-to-oldest brother is 5 years older than she is, and the youngest brother is twice Maria's age.
\n" ); document.write( " What are the ages of the Jones' four children?
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\n" ); document.write( "Let m = M's age
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "\"Maria's oldest brother is six times as old as she is.
\n" ); document.write( "6m = oldest brother
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\n" ); document.write( "\"Her next-to-oldest brother is 5 years older than she is,\"
\n" ); document.write( "m+5 = next brother
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\n" ); document.write( "\" the youngest brother is twice Maria's age.\"
\n" ); document.write( "2m = youngest brother
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\n" ); document.write( "\"The sum of the ages of Jones' four children is 25.
\n" ); document.write( "6m + (m+5) + 2m + m = 25
\n" ); document.write( "10m = 25 - 5
\n" ); document.write( "10m = 20
\n" ); document.write( "m = 2 yrs is M's age
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\n" ); document.write( "You can find the ages of the brothers from this\r
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