document.write( "Question 602572: 2x-1/3=4x+3=?.please help. \n" ); document.write( "
Algebra.Com's Answer #380353 by rfer(16322)\"\" \"About 
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-2x=3 1/3
\n" ); document.write( "-2x=10/3
\n" ); document.write( "x=(10/3)/-2
\n" ); document.write( "x=10/3*-1/2
\n" ); document.write( "x=-10/6
\n" ); document.write( "x=-1 2/3
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