document.write( "Question 602605: We are currently working with linear functions and there is a story problem I cannot seem to understand:\r
\n" ); document.write( "\n" ); document.write( "A person invested $17,000 for one year, part at 10%, part at 12%, part at 15%. The total annual income from these investments was $2,110. The amount of money invested at 12% was $1,000 less than the amount invested at 10% and 15% combined. Find The amount invested at each rate.
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Algebra.Com's Answer #380342 by stanbon(75887)\"\" \"About 
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A person invested $17,000 for one year, part at 10%, part at 12%, part at 15%. The total annual income from these investments was $2,110. The amount of money invested at 12% was $1,000 less than the amount invested at 10% and 15% combined. Find The amount invested at each rate.
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\n" ); document.write( "Equations:
\n" ); document.write( "a + b + c = 17000
\n" ); document.write( "0.10a + 0.12b + 0.15c = 2110
\n" ); document.write( "b = (a+c-1000)
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\n" ); document.write( "Rearrange and modify:
\n" ); document.write( "a + b + c = 17000
\n" ); document.write( "10a + 12b + 15c = 211000
\n" ); document.write( "a - b + c = 1000
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\n" ); document.write( "Using any method you know, solve for a, b, c:
\n" ); document.write( "a = 4000
\n" ); document.write( "b = 8000
\n" ); document.write( "c = 5000
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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