document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602472>Question 602472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi tutors. Please help me verify that this equation is an identity.\r<BR>\n" );
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document.write( "[(sin^3 A) + (cos^3 A)]/(sinA +cosA)  =  1 - (sinA)(cosA)\r<BR>\n" );
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document.write( "Please show the steps if you can so that I can follow how to arrive at the correct answer. Thank you so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380287 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi tutors. Please help me verify that this equation is an identity. <BR>\n" );
document.write( "[(sin^3 A) + (cos^3 A)]/(sinA +cosA) = 1 - (sinA)(cosA)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Use sum of cubes formula to solve:<BR>\n" );
document.write( "x^3+y^3=(x+y)(x^2-xy+y^2)<BR>\n" );
document.write( "For given problem:<BR>\n" );
document.write( "Start with left side:<BR>\n" );
document.write( "(sin^3+cos^3)/(sin+cos)<BR>\n" );
document.write( "=[(sin+cos)(sin^2-sincos+cos^2)]/(sin+cos)<BR>\n" );
document.write( "sin^2+cos^2=1<BR>\n" );
document.write( "(sin+cos) cancels out<BR>\n" );
document.write( "=1-sincos<BR>\n" );
document.write( "verified:<BR>\n" );
document.write( "left side=right side </SPAN>\n" );
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