document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602457>Question 602457</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Whats the solution to this equation: Two angles are supplementary. The measure of one angle is 10 more than three times the other. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380267 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Whats the solution to this equation: Two angles are supplementary. The measure of one angle is 10 more than three times the other. Find the measure of each angle.<BR>\n" );
document.write( "------<BR>\n" );
document.write( "x + y = 180<BR>\n" );
document.write( "x = 3y+10<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Substitute for \"x\" and solve for \"y\":<BR>\n" );
document.write( "3y+10 + y = 180<BR>\n" );
document.write( "4y = 170<BR>\n" );
document.write( "y = 42.5 degrees<BR>\n" );
document.write( "x = 3y+10 = 137.5 degrees<BR>\n" );
document.write( "============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );