document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602443>Question 602443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi. How do I prove this equation to be an identity?\r<BR>\n" );
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document.write( "(tanY + sec^2 Y - tan^2Y)/secY = sinY + cosY\r<BR>\n" );
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document.write( "Everytime I solve this I always end up with 1 - sinY cosY = sin Y + cos Y\r<BR>\n" );
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document.write( "I really don't know what I should do here so I hope you can help me and show me how to do this. Thank you in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380240 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (tanY + sec^2 Y - tan^2Y)/secY = sinY + cosY \r<BR>\n" );
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document.write( "(tanY + 1)/secY = sinY + cosY \r<BR>\n" );
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document.write( "tanY/secY + 1/secY = sinY + cosY \r<BR>\n" );
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document.write( "(sinY/cosy)/(1/cosY) + 1/(1/cosY) = sinY + cosY \r<BR>\n" );
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document.write( "(sinY/cosy)*(cosY/1) + cosY = sinY + cosY \r<BR>\n" );
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document.write( "(sinYcosY)/cosY + cosY = sinY + cosY \r<BR>\n" );
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document.write( "sinY + cosY = sinY + cosY \r<BR>\n" );
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document.write( "So this verifies the identity. </SPAN>\n" );
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