document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602332>Question 602332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help please on Permutations.\r<BR>\n" );
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document.write( "Problem:<BR>\n" );
document.write( "how many ways can 15 students be separated into two groups of 8 and 7?\r<BR>\n" );
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document.write( "Attempt:<BR>\n" );
document.write( "Since they will be separated into 2 groups, i tried using 15!/7! since the rest (those seven left) will be on the other group, but it does not show the combinations for the other group. And so i am wrong. :/ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380207 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the order that people are placed into a group is not a factor, so this is a combination question (not permutation)\r<BR>\n" );
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document.write( "this is kind of a \"trick\" question ___ if x + y = z ; then zCx = zCy\r<BR>\n" );
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document.write( "ALL the students will be assigned to one group or the other<BR>\n" );
document.write( "___ the possible combinations of the two groups are concurrent ___ 15C8 is the same as 15C7<BR>\n" );
document.write( "___ separating groups of 8 concurrently separates groups of 7<BR>\n" );
document.write( "___ for every group of 8; there will automatically be a complementary group of 7\r<BR>\n" );
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document.write( "so the answer is 15C8 (or 15C7) </SPAN>\n" );
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