document.write( "Question 602299: Please help me to answer this problem:\r
\n" ); document.write( "\n" ); document.write( "There are 40 Liters of 50% acid solution that should be reduced to a 40% acid solution. How much of acid solution must be drained off with distilled water so that the resulting solution contains only 40% acid?
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Algebra.Com's Answer #380201 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Acid Solution I 50.00% ---------------- x liters
\n" ); document.write( "Water 0.00% ------ 40 - x liters
\n" ); document.write( "Mixture 40.00% ---------------- 40
\n" ); document.write( "50.00%x+ 0.00%(40-x)=40.00%*40
\n" ); document.write( "50x+0(40 -x)=1600
\n" ); document.write( "50x =1600
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\n" ); document.write( "/ 50
\n" ); document.write( " x = 32 liters 50.00% Acid Solution I
\n" ); document.write( " 8 liters Water
\n" ); document.write( " 8 liters will have to be drained off
\n" ); document.write( "m.ananth@hotmail.ca
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