document.write( "Question 602331: What is the center of the circle defined by the equation (x+5)^2+(y-1)^2=36 \n" ); document.write( "
Algebra.Com's Answer #380193 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! What is the center of the circle defined by the equation (x+5)^2+(y-1)^2=36 \n" ); document.write( ". \n" ); document.write( "Standard equation of a circle: \n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2 \n" ); document.write( "where \n" ); document.write( "(h,k) is the center \n" ); document.write( "r is the radius \n" ); document.write( ". \n" ); document.write( "You were given: \n" ); document.write( "(x+5)^2+(y-1)^2=36 \n" ); document.write( "which can be written as: \n" ); document.write( "(x-(-5))^2+(y-1)^2=36 \n" ); document.write( "so, from inspection then, the center is at: \n" ); document.write( "(-5, 1) \n" ); document.write( " \n" ); document.write( " |