document.write( "Question 602331: What is the center of the circle defined by the equation (x+5)^2+(y-1)^2=36 \n" ); document.write( "
Algebra.Com's Answer #380193 by nerdybill(7384)\"\" \"About 
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What is the center of the circle defined by the equation (x+5)^2+(y-1)^2=36
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\n" ); document.write( "Standard equation of a circle:
\n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2
\n" ); document.write( "where
\n" ); document.write( "(h,k) is the center
\n" ); document.write( "r is the radius
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\n" ); document.write( "You were given:
\n" ); document.write( "(x+5)^2+(y-1)^2=36
\n" ); document.write( "which can be written as:
\n" ); document.write( "(x-(-5))^2+(y-1)^2=36
\n" ); document.write( "so, from inspection then, the center is at:
\n" ); document.write( "(-5, 1)
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