document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602306>Question 602306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	Find the domain of the function f(x) = ln(3x + 36). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380182 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the domain of the function f(x) = ln(3x + 36).<BR>\n" );
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document.write( "Domain defines all possible values x can take...<BR>\n" );
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document.write( "Since, you can't take ln of a negative number, we have:<BR>\n" );
document.write( "3x + 36 >= 0<BR>\n" );
document.write( "3x >= -36<BR>\n" );
document.write( "x >= -12  (this is your answer)<BR>\n" );
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document.write( "Or, it could be written as:<BR>\n" );
document.write( "[-12, +oo)<BR>\n" );
document.write( "where +oo means positive infinity </SPAN>\n" );
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