document.write( "Question 602278: Please help me, I am so lost. The problem is: solve the equation on the interval 0 is less than or equal to theta, theta is less that or equal to 2pi.
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document.write( "the equation: cos theta/2 = sec theta/2 \n" );
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Algebra.Com's Answer #380178 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! To simplify the notation, let x=theta \n" ); document.write( "cos(x/2) = sec(x/2) = 1/cos(x/2) \n" ); document.write( "This gives cos^2(x/2) = 1 \n" ); document.write( "Using the identity cos^2(x/2) = 1/2(1+cos(x)), we can write \n" ); document.write( "1/2(1+cos(x)) = 1 \n" ); document.write( "This gives \n" ); document.write( "cos(x) = 1 \n" ); document.write( "On the interval 0 <= x <= 2 |