document.write( "Question 602278: Please help me, I am so lost. The problem is: solve the equation on the interval 0 is less than or equal to theta, theta is less that or equal to 2pi.
\n" ); document.write( "the equation: cos theta/2 = sec theta/2
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Algebra.Com's Answer #380178 by htmentor(1343)\"\" \"About 
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To simplify the notation, let x=theta
\n" ); document.write( "cos(x/2) = sec(x/2) = 1/cos(x/2)
\n" ); document.write( "This gives cos^2(x/2) = 1
\n" ); document.write( "Using the identity cos^2(x/2) = 1/2(1+cos(x)), we can write
\n" ); document.write( "1/2(1+cos(x)) = 1
\n" ); document.write( "This gives
\n" ); document.write( "cos(x) = 1
\n" ); document.write( "On the interval 0 <= x <= 2\"pi\", the solutions are 0 and 2\"pi\"
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