document.write( "Question 602153: Trains A and B are traveling in the same direction on parallel
\n" ); document.write( "track. Train A is traveling at 80 miles per hour and train B is
\n" ); document.write( "traveling at 100 miles per hour. Train A passes a station at 3:20 am.
\n" ); document.write( "If train B passes the same station at 3:35 am ., at what time will
\n" ); document.write( "train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #380146 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
the distance traveled by both is same when one catches up with the other.
\n" ); document.write( "Let them meet at distance x
\n" ); document.write( "Train A speed= 80 mph , starts at 03:20 pm
\n" ); document.write( "Train B speed= 100 mph starts at 03:35 pm
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\n" ); document.write( "Time difference between the starting of the two= 0.25 hours
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\n" ); document.write( "Time taken by Train A = X / 80
\n" ); document.write( "Time taken by Train B = X / 100
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\n" ); document.write( "X / 80 - X / 100 = 0.25
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\n" ); document.write( "LCD - 400
\n" ); document.write( "Multiply equation by 400
\n" ); document.write( "400 / 80 x- 400 / 100 x= 0.25 * 400
\n" ); document.write( "5 x - 4 x = 100
\n" ); document.write( "1 x = 100
\n" ); document.write( "/ 1
\n" ); document.write( "x= 100 miles
\n" ); document.write( "Train A speed= 80 mph
\n" ); document.write( "Distance = 100 miles
\n" ); document.write( "Time taken = 100 / 80
\n" ); document.write( "Time taken = 1.25 hour
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\n" ); document.write( "They will be together at 04:35 pm \r
\n" ); document.write( "\n" ); document.write( "Train B catches up at 4:35 pm
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\n" ); document.write( "m.ananth@hotmail.ca
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