document.write( "Question 602154: Larry invested part of his $38,000 advance at 6% annual simple interest and the rest at 9% annual simple interest. If his total yearly interest from both accounts was $2,850, find the amount invested at each rate. At 6% and 9%. \n" ); document.write( "
Algebra.Com's Answer #380142 by mananth(16946)\"\" \"About 
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Part I 6.00% per annum ------------- x
\n" ); document.write( "Part II 9.00% per annum ------------ y
\n" ); document.write( " 38000
\n" ); document.write( "Interest----- 2850
\n" ); document.write( "
\n" ); document.write( "Part I 6.00% per annum ---x
\n" ); document.write( "Part II 9.00% per annum ---y
\n" ); document.write( "Sum of investments
\n" ); document.write( "x + 1 y= 38000 -------------1
\n" ); document.write( "Interest earned on both investments
\n" ); document.write( "6.00% x + 9.00% y= 2850
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 9 y= 285000.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -228000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 3 y= 57000
\n" ); document.write( "divide by 3
\n" ); document.write( " y = 19000
\n" ); document.write( "Part I 9.00% $ 19000
\n" ); document.write( "Part II 6.00% $ 19000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "19000 --------- 9.00% ------- 1710.00
\n" ); document.write( "19000 ------------- 6.00% ------- 1140.00
\n" ); document.write( "Total -------------------- 2850.00
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\n" ); document.write( "m.ananth@hotmail.ca
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