document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=602120>Question 602120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the second angle is a triangle is one and a half times the measure of the first. the third is 15 degree more than half the first angle. find the measure of each angles in the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #380135 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=380135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the second angle is a triangle is one and a half times the measure of the first. the third is 15 degree more than half the first angle. find the measure of each angles in the triangle<BR>\n" );
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document.write( "Let 1st be \"x\"<BR>\n" );
document.write( "Then 2nd is 1.5x<BR>\n" );
document.write( "And 3rd (x/2)+15<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + 1.5x + (x/2) + 15 = 180<BR>\n" );
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document.write( "2x + 3x + x  = 360-30<BR>\n" );
document.write( "6x = 330<BR>\n" );
document.write( "x = 55<BR>\n" );
document.write( "1st = x = 55 degrees<BR>\n" );
document.write( "2nd = 82.5 degrees<BR>\n" );
document.write( "3rd = 42.5 degrees<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============================  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );